First midterm: tonight at 7 pm in McKenzie 240C

Covers weeks 1-3 (lectures 1-9, homework 1-3, lab 1-3).

Bring a calculator

The exam is closed note; however, there is a data sheet on the back page with important formulas and constants.

You may use a calculator on the exam, but no Internet-enabled device (cell phone, tablet, laptop, etc).

Enzymes: mechanism of serine protease

2017-10-18


Enzymes work by:

  1. Destabilizing the substrate
  2. Increasing the effective temperature of the reaction
  3. Stabilizing the transition state

Stabilizing the transition state

A small decrease in "activation" energy ($\Delta \Delta G$) gives:

  1. A linear increase in rate ($\frac{k_{enz}}{k_{non}} \sim \Delta \Delta G$)
  2. A quadratic increase in rate ($\frac{k_{enz}}{k_{non}} \sim \Delta \Delta G^{2}$)
  3. An exponential increase in rate ($\frac{k_{enz}}{k_{non}} \sim e^{\Delta \Delta G}$)
  4. A sinusoidal increase in rate ($\frac{k_{enz}}{k_{non}} \sim sin(\Delta \Delta G$))

An exponential increase in rate ($\frac{k_{enz}}{k_{non}} ~ e^{\Delta \Delta G}$)

Conceptual goals

  • Understand the chemical mechanism of serine protease.
  • Understand the core ways enzymes speed up rates: orient substrates, sequester from water, interact with transition state, do sequential low barrier chemical steps.

Skill goals

  • Trace/explain the electron "arrows" in this mechanism.
  • Reason about the effects of mutations on its activity.

Peptide bond is a hydrolysis reaction

rate constant = $k = 1.5 \times 10^{-9}\ s^{-1}$

$k = 0.05\ years^{-1}$. That means 20 years to break a bond!

The "Active Site" is where the chemistry happens

Made of Asp-His-Ser catalytic triad

Active site pulled away from water

The catatlyic triad is made of Asp-His-Ser

Step 1: $R-S^{-}$ attack on carbonyl

Puzzles:

  • Serine (ROH) is a pretty weak nucleophile (about as good as water). How can it lead to rate speed up relative to water? $R-O^{-}$ is an excellent nulceophile ($\approx 10^{8}$ better than water).
  • But the $pK_{a}$ of Serine proton is $\approx 17$. What business does it have giving up a proton at $pH$ 7? Triad shifts $pK_{a}$ of serine

  • Aspartic acid away from water desperately needs to fulfill its interactions

    The negative aspartic acid can form a (quasi) ionic bond if Histidine protonates and becomes positive

    His pulls on the Ser proton, lowering its $pK_{a}$ to near neutral.

    Big ideas

    1. Enzymes orient chemical groups so they're primed to do chemistry.

    2. Enzymes activate polar atoms by pulling them away from water.

    Step 1: $R-S^{-}$ attack on carbonyl

    This creates a negatively charged tetrahedral intermediate

    Oxyanion hole stabilizes tetrahedral intermediate by interacting with negative oxygen


    Credit: oregonstate.edu

    Big ideas

    1. Enzymes orient chemical groups so they're primed to do chemistry.

    2. Enzymes activate polar atoms by pulling them away from water.

    3. Enzymes interact with/stabilize transition state.

    Step 2: break the peptide bond

    Electrons flow from negative oxygen, but rather than breaking new peptide-serine bond, break peptide bond to satisfy electron-poor histidine

    Newly cleaved C-terminal bit leaves the active site by diffusion. Remainder of peptide covalently attached to Serine.

    Step 2: break the peptide bond

    Step 3: newly cleaved C-terminal peptide diffuses away

    Are we done yet?

    No. Enzyme still has peptide covalently attached.

    Step 3: newly cleaved C-terminal peptide diffuses away

    Step 4: water enters the binding site and attacks peptide carbonyl

    Water is "activated" by that needy histidine in the same way as Serine

    Step 4: water enters the binding site and attacks peptide carbonyl

    Step 5: electrons flow from charged oxygen and break peptide-serine bond

    Step 6: newly cleaved peptide diffuses out of active site, enzyme restored

    Big ideas

    1. Enzymes orient chemical groups so they're primed to do chemistry.

    2. Enzymes activate polar atoms by pulling them away from water.

    3. Enzymes interact with/stabilize transition state.

    4. Enzymes do hard chemistry by breaking it into multiple, low-barrier steps

    Specifcity is achieved by polar interactions outside of active site

    Tobacco Etch Virus protease recognizes ENLYFQG

    Big ideas

    1. Enzymes orient chemical groups so they're primed to do chemistry.

    2. Enzymes activate polar atoms by pulling them away from water.

    3. Enzymes interact with/stabilize transition state.

    4. Enzymes do hard chemistry by breaking it into multiple, low-barrier steps

    5. Specificity is encoded by interactions near the active site

    Exact active site geometry has evolved many times

    Class review

    Let's have a different person answer each question

    Step 0: primed catalytic triad

    Why is the Asp-His hydrogen bond strong? Both are away from water in the active site

    Step 0: primed catalytic triad

    How does this change the strength of the His-Ser H-bond? Negative Asp stabilizes positive His, increasing affinity of His for proton

    Step 1: $R-S^{-}$ attack on carbonyl

    How can a Ser ($pK_{a}\ 17$) deprotonate at $pH\ 7$? The needy His "pulls" on the Ser proton and thus lowers the $pK_{a}$ of Ser.

    Step 1: $R-S^{-}$ attack on carbonyl

    Is this activated Ser a better or worse nucleophile than water? Much better

    Step 2: break the peptide bond

    How does the enzyme stabilize the negative tetrahedral intermediate? Favorable polar interactions with negative charge (oxyanion hole)

    Step 2: break the peptide bond

    Why does the peptide bond break rather than the Ser-peptide bond? Histidine is now formally positive and is now more attractive to electrons than the Ser

    Step 3: newly cleaved C-terminal peptide diffuses away

    Step 4: water enters the binding site and attacks peptide carbonyl

    What business does a water molecule have in a (relatively) hydrophobic active site? 1. Water is 55 M. 2. lone pair on histidine nitrogen needs an acceptor.

    Step 5: electrons flow from charged oxygen and break peptide-serine bond

    Step 6: newly cleaved peptide diffuses out of active site, enzyme restored

    Big ideas

    1. Enzymes orient chemical groups so they're primed to do chemistry.

    2. Enzymes activate polar atoms by pulling them away from water.

    3. Enzymes interact with/stabilize transition state.

    4. Enzymes do hard chemistry by breaking it into multiple, low-barrier steps

    5. Specificity is encoded by interactions near the active site