Cooperativity: how does hemoglobin load and unload oxygen? 
					2017-10-25
					
				
				
					Conceptual goals
                    
                        - Understand how multiple subunits working in conjunction give tightly controlled loading and unloading of cooperative proteins.
 
                    
					Skill goals
                    
                        - Reason about the thermodynamics of cooperativity using linkage thermodynamics.
 
                        - Interpret graphical representations of loading/unloading curves in terms of cooperative behavior.
 
                    
				
                
                
                
                    Hemoglobin is a tetramer four proteins
                    
                
                
                
                    Transition is cooperative (either one state or other -- no intermediate state)
                    
                                   
                
                    Interfaces lead to cooperativity by linking subunits
                    
                                   
                 
                
                
                    Summary I
                    
                        - Myoglobin and hemoglobin are $O_{2}$ binding proteins that bind $O_{2}$ using a "heme" group
 
                        - Hemoglobin is a tetramer of myoglobin-like subunits
 
                        - Myoglobin buffers $O_{2}$ in tissues, hemoglobin transports $O_{2}$ in the blood
 
                        - Myoglobin would unload at most 10% of its $O_{2}$ if it transported oxygen
 
                        - Best monomer ($K_{D}=44\ torr$) could unload 40% of its oxygen
 
                    
                
                
                    Summary II
                    
                        - Cooperativity between sites allows hemoglobin to unload 75% of oxygen
 
                        - Cooperativity comes about because binding the first $O_{2}$ "pays" to put complex into high $O_{2}$ affinity state.
 
                        - This is descibed by the "Hill equation":$$\theta_{Hill} = \frac{1}{1 + (K_{D}/[L])^{n}}$$ where $n$ is $\approx$ number of sites