$C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O$
What type of reaction is this?
Combustion reaction
 publicdomainimages.net
                    publicdomainimages.net
                How do living things avoid burning up?

Worksheet
$O_{2} + 2H_{2} \rightarrow 2H_{2}O$
Products:
Reactants:
Estimating $\Delta H^{\circ}$
$(O=O) + (2\times H-H) \rightarrow (4 \times O-H)$
$(498) + (2\times 436) \rightarrow (4 \times 464)$
$1370 \rightarrow 1856$
$1856 - 1370 = 486$
$\Delta = 486\ kJ\cdot mol^{-1}$
This is exothermic, as it is more unfavorable to break product bonds than reactant bonds
Why is this reaction exothermic?
Is $H_{2}$ oxidized or reduced in this reaction?
Oxidized. Hydrogens lose electrons (which are now "owned" by oxygen)
NOTE: REDOX reactions are always paired $H_{2}$ was oxidized, $O_{2}$ was reduced
If an $ADP+P_{i}\rightarrow ATP$ takes $30.5\ kJ\cdot mol^{-1}$, how many $ATP$ could you form with this reaction?
$486/30.5 = 15.9 ATP$.
$ATP \rightarrow ADP + P_{i}$
 
                             
                                 
                                $C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O$
electrons are transferred from $C_{6}H_{12}O_{6}$ and $O_{2}$ to $CO_{2}$ and $H_{2}O$
To break up reaction into steps, we need way to temporarily hold on to electrons
$NAD^{+} + H^{-} \rightarrow NADH$
 
                             
                            Finally: REDOX potentials measure electron affinity
Tables show reduction reactions
MORE POSITIVE MEANS HIGHER AFFINITY
 
                Summary: