Oxidative Phosphorylation II

2017-11-20


Conceptual goals

  • Understand how the electron transport chain couples movement of electrons along a REDOX gradient to creating a proton gradient
  • Understand how different cofactors can safely shuttle electrons

Skill goals

  • Reason about the linkage between changes in reduction potential and ability to transport protons against a concentration gradient
  • Reason about the relative ordering of the electron transport chain based on REDOX potentials and perturbation with drugs

Oxidative phosphorylation overview:


Why does oxidative phosphorylation break the $NADH + \frac{1}{2}O_{2} + H^{+} \rightarrow NAD^{+} + H_{2}O$ reaction into multiple steps?

Control, capture of energy at each step

Where does ox-phos occur (and which way are protons pumped)?

In the mitochondria, pumping protons from matrix into intermembrane space

Complex I couples oxdiation of $Q$ to $QH_{2}$ to transport of protons across the bilayer

Process has many sequential steps

$NAD:H + H^{+} + FMN \rightarrow FMNH_{2}$

$FMNH_{2} + 2Fe^{3+} \rightarrow FMN + H_{2} + 2Fe^{2+}$

Pass along several iron-sulfur clusters

$2Fe^{3+} + 2Fe^{2+} \rightarrow 2Fe^{2+} + 2Fe^{3+}$

$2Fe^{2+} + Q + 2H^{+} \rightarrow 2Fe^{3+} QH_{2}$

FMN accepts electrons directly from NADH

Iron-sulfur clusters

Iron-sulfur clusters

  • Driven by oxidation of $Fe^{2+}$ to $Fe^{3+}$.
  • Single electron transfer
  • Sulfur complexes hold $Fe$ iron away from water and physically links oxidation state of $Fe$ to rest of protein

The mysterious $Q$ (ubiquinone, coenzyme Q10)


Source: examine.com

Ubiquinone

  • Driven by oxidation carbonyl/hydroxyls on conjugated ring

  • Two electron transfer
  • Both oxidized and reduced forms are uncharged. Diffuses in the bilayer
Fe-Sulfur clusters form a chain. Electrons pass through chain, eventually hopping onto $Q$ to from $QH^{2}$ in the bilayer.

Key point: the $2H^{+}$ come from the matrix side

Transfer is also linked to transfer of four more protons...somehow.

Complex I is not the only source of $QH_{2}$.

Succinate enters oxidative phosphorylation via Complex II, generating $QH_{2}$

Fatty acid oxidation, other oxidation reactions can generate $QH_{2}$ using a variety of enzymes

What happens to $QH_{2}$?


Enters "Q-cycle" which ultimately oxidizes cytochrome C and moves $4H^{+}$ across the bilayer

$2QH_{2} \rightarrow QH_{2} + Q + 2H^{+}$

Key point: this is an indirect pump. Geometry of complex III means protons are preferentially picked up on matrix side, preferentially dropped on lumen side

Oxidative phosphorylation overview:


Cytochromes

  • Driven by oxidation of $Fe^{2+}$ to $Fe^{3+}$.
  • Single electron transfer
  • Heme holds $Fe$ iron away from water and physically links oxidation state of $Fe$ to rest of protein

Cytochromes hold onto this heme ring in a deep pocket, protecting Fe

Cytochrome c is a "peripheral" membrane protein that "skates" over to complex IV

Oxidative phosphorylation overview:


Complex IV uses $O_{2}$ to oxidize $CytC(Fe^{2+})$.

$4\ CytC(Fe^{2+}) + O_{2} + 4H^{+} \rightarrow 4\ CytC(Fe^{3+}) + 2H_{2}O$


This transports 2 more protons across the bilayer


Why might succinate to fumarate come in to ox-phos directly as $QH_{2}$ (rather than going through complex I)?

Does this give as much energy as an NADH?

$succinate$ has higher affinity for $e^{-}$ than $NADH$

$fumarte + 2H^{+} + 2e^{-} \rightarrow succinate^{-}$, $\varepsilon^{\circ \prime} = 0.031 \ V$

$NAD^{+} + H^{-} \rightarrow NADH$, $\varepsilon^{\circ \prime} = -0.315 \ V$

4 fewer protons are transported for succinate than $NADH$: lower energy yield

Highest yield step?

$QH_{2} \rightarrow cytochrome\ C$

Surprising?

Why not transport more $H^{+}$ at the $O_{2}$ step? I'm not sure, actually

Why might electron transfers be so tightly controlled?

Premature contact with $O_{2}$ can generate highly reactive $\cdot O_{2}^{-}$ radical.

Summary I

  • Passage through Complexes I-IV allows oxidation of $NADH$ and other biomolecules, ultimately reducing $O_{2}$.
  • This transports a total of 10 protons out of mitochondrial matrix
  • This "recycles" $NADH$ and $QH_{2}$ into their oxidized forms

Summary II

  • REDOX centers (Fe-S, hemes, Q, cytochromes) allow ordered, vectorial movement of electrons towards increased reduction potentials
  • Integral redox centers couple electron transport to allosteric conformational changes in complexes
  • Allosteric conformational changes in complexes lead to transport of protons